Sunday 24 October 2010

MATHS PUZZLE #4 -First Leg, Second Year-

(from the 25th October to the 2nd November)

ELECTIONS

In a particular country´s latest elections, in which there were 3,456,000 votes and 4 candidates, the winner defeated the other three opponents by 134,890, 64,500 and 15,490 votes respectively.
However, none of them managed to know the exact number of votes that each one received.
How could we get this information? 
You can send the solution to FernandoEscuin@iescampanar.com

SOLUTION

The numbers of votes are: x, y, z and t. Where x  is the votes of the winner.
We have:
x + y +z + t = 3.456.000
x= 134. 890 + y
x = 64500 + z
x = 15.490 + t
Summing the last three equalities:
3x = 214.880 + y + z + t
Now, summing x to the two sides:
4x = 214.880 + x + y + z + t
4x = 214.880 + 3.456.000
4x = 3.670. 880
x= 3.670.880/4
x= 917.720 votes
y = 782.830 votes
z = 853.220 votes
t = 902.230 votes

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