MATHS PUZZLE # 11 SECOND LEG

   (From the 10th to the 16th of January 2010) 

Determine a series of 12 natural numbers in which the fourth term is 4, the twelfth term is 12 and the sum of ANY three consecutive terms is 50.

You can send your answers to matecampanar@gmail.com

SOLUTION

The number is: abcdefghijkl

If l = 12 → j+k =38 → i=12 → g+h = 38 → f= 12 →d+e = 38 →e=34 → g = 4 → h = 34 →

j = 4 → k = 34

Because of d+e = 38 → c=12 →b=34 →a =4

Consequently the number is: 4;12;34;4;12;34;4;12;34;4;12;34

-----The next puzzle to be posted on the 23rd of January-----